Answer :

Given:
Distance between the coin and the floor of the elevator before the coin is dropped = 6 ft
Let, a= the acceleration of the elevator.



It is given that the coin reaches the floor in 1 second. This means that the coin travels 6 ft distance.



The initial velocity is u for the coin and 0 for the elevator.
Using the equation of motion, we get:
Equation for the coin:


=


Here,
a‘= ga (a‘ is the acceleration felt by the coin.)
g = Acceleration due to gravity
g = 9.8 m/s2 = 32 ft/s2
on substituting the values, we get:


=


=


Therefore, we can write:





Hence, the acceleration of the elevator is 20 ft/s2.


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