Q. 104.8( 6 Votes )

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Answer :

Given: mass of number of X = 35

No. of neutrons = 18

Atomic number of element X = Mass number – no. of neutrons present

Atomic no. = 35 -18 = 17

The electronic configuration of X will be 2, 8, 7

X will belong to group no. 10 + 7= 17th

X will belong to period 3rd as it has three shells.

Since it requires one more electron to get stable gas electron configuration, so the valency is 1.


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