Q. 115.0( 2 Votes )

An element crysta

Answer :

As it is face lattice,

No of atoms per unit cell (z) =4

Edge length (a)=400pm = 400*10-10cm

Density (d)=7g/cm3

Mass =280g

No .of atoms =?

Volume of cell V=a3=(400*10−10)3=64*10−24cm3

Volume of 280 g of element =m/d



No .of unit in 40cm3=




In FCC each unit cell contain 4 atoms .

Hence total number of atoms in 6.25×1023

units cells are



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