Answer :

Given:

Power of an electrical device: P = 2kW

voltage: V = √50000 V

RMS value of voltage : V_{RMS} = 223 V

tanϕ = -3/4

Formula used:

(i)

Power is given as

Here, P is the power, V is the voltage,I is the current and Z is the impedance.

Also, V^{2} = 50000 V

We know that as X_{C}>X_{L}

Here, R is the resistance of the circuit, X_{L} is the inductive reactance and X_{C} is the Capacitive reactance.

Also,

Substituting we get,

(ii)

Substituting value of R we get,

(iii)

I_{M} = I_{o}. Here I_{o} is the output current.

RMS value of current is

Also,

Now, if values of R, X_{C} and X_{L} are doubled.

Then value of tanϕ would remain same. Value of Z will be doubled. As power and impedance have inverse relation. Power would become half .

Hence, doubling the values of R, X_{C} and X_{L} would make the power half times the present one.

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