Answer :


Given


The operating voltage is V and power consumed is P.



Therefore, the resistance of the bulb can be calculated as follows,




Putting the values in the above formula, we get




The power fluctuations is given as p = 150 W


So, the voltage fluctuation that the bulb can withstand is given by-


Resistance of the bulb,


Where


V is the velocity


P is the power fluctuations






Hence the bulb will withstand fluctuations up to 270 V.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

An electric bulb HC Verma - Concepts of Physics Part 2

A servo voltage sHC Verma - Concepts of Physics Part 2

Figure shows an eHC Verma - Concepts of Physics Part 2

Find the charge rHC Verma - Concepts of Physics Part 2

Find the thermo-eHC Verma - Concepts of Physics Part 2

The 2.0 Ω resistoHC Verma - Concepts of Physics Part 2

An immersion heatHC Verma - Concepts of Physics Part 2

An electric bulb,HC Verma - Concepts of Physics Part 2

A coil of resistaHC Verma - Concepts of Physics Part 2

When a current paHC Verma - Concepts of Physics Part 2