An arrow 2.5cm high is placed at a distance of 25 cm from a diverging mirror of focal length 20 cm. Find the nature, position and size of the image formed.
Height of object = 2.5cm
Object distance from mirror = -25cm
Focal length = -20cm
Using the mirror formula,
Image distance, v = 11.1 cm
Thus, the image is formed 11.1 cm behind the convex mirror and is Virtual and erect.
Magnification, m = v/u = 1.1 cm tall
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