Q. 5

# An arrow 2.5cm high is placed at a distance of 25 cm from a diverging mirror of focal length 20 cm. Find the nature, position and size of the image formed.

Answer :

Height of object = 2.5cm

Object distance from mirror = -25cm

Focal length = -20cm

Using the mirror formula,

Image distance, v = 11.1 cm

Thus, the image is formed 11.1 cm behind the convex mirror and is Virtual and erect.

Magnification, m = v/u = 1.1 cm tall

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