Answer :


Given;


Mass of aluminium=0.5kg


mass of water=0.2kg


Mass of iron=0.2kg


temperature of aluminium vessel and water=20c


Temp of iron=100c


heat capacity of aluminium=910 J/kg-k


heat capacity of iron=470J/kg-k


heat capacity of water=4200J/kg-k


Formula used:


ΔQ=mCΔT


ΔQ=heat exchange


ΔT=tempeature change


M=mass


C=heat capacity


let the dinal temperature of the mixture be T;


so;




as


heat gain by aluminum and water=heat loss by iron





T=298.41k


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