# An aluminum vesse

Given;

Mass of aluminium=0.5kg

mass of water=0.2kg

Mass of iron=0.2kg

temperature of aluminium vessel and water=20c

Temp of iron=100c

heat capacity of aluminium=910 J/kg-k

heat capacity of iron=470J/kg-k

heat capacity of water=4200J/kg-k

Formula used:

ΔQ=mCΔT

ΔQ=heat exchange

ΔT=tempeature change

M=mass

C=heat capacity

let the dinal temperature of the mixture be T;

so;

as

heat gain by aluminum and water=heat loss by iron

T=298.41k

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