# An alpha particle is projected vertically upward with a speed of 3.0 × 104 kg s–1 in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force that acts on the α-particle.

Given -

Speed of the alpha particle in upward direction,

v = 3 × 104 km/s

since 1Km = 1000m

v = 3 × 107 m/s

Magnetic field, B = 1.0 T

Charge on the alpha particle is given as , where e is the charge of an electron.

q = 2 × 1.6 × 10−19 C,

We need to calculate the magnetic force that acts on the α-particl The direction of magnetic force can be found using Fleming’s left-hand rule.

The direction of the magnetic field is from south to north.

We know, Lorentz force F is given by - where,

q = charge

v = velocity of the charge

B=magnetic field

and

θ= angle between V and B

Now, magnetic force acting on the α -particle, Substituting the values = 2 × 1.6 × 10−19 × 3 × 107 × 1

= 9.6 × 10−12 N

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