Answer :

The compounds A, B , C are


2 Methyl but-2-ene, Acetaldehyde and acetone respectively.

Among B and C former is an aldehyde(responds to Felling’s test) and latter is obviously a ketone as both forms iodoforms on treatment with I2 and NaOH. And from this clue, we can identify the alkene ‘A’ (Mol. formula C5H10) which is 2 Methyl but-2-ene also as ozonolysis does not disrupt the symmetry of the molecule.

The equation for ozonolysis of alkene
A :

‘A’ ‘ C’ ‘B’

Now, for compound ‘B’ (acetaldehyde) the iodoform reaction is as follows :

It also gives Felling’s test which is the way to identify it as an aldehyde :

Compound ‘C’ which is a ketone (acetone) the iodoform reaction is as follows:

But it is unable to give Fehling’s test.

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