Answer :

The compounds A, B , C are

,


2 Methyl but-2-ene, Acetaldehyde and acetone respectively.


Among B and C former is an aldehyde(responds to Felling’s test) and latter is obviously a ketone as both forms iodoforms on treatment with I2 and NaOH. And from this clue, we can identify the alkene ‘A’ (Mol. formula C5H10) which is 2 Methyl but-2-ene also as ozonolysis does not disrupt the symmetry of the molecule.


The equation for ozonolysis of alkene
A :



‘A’ ‘ C’ ‘B’


Now, for compound ‘B’ (acetaldehyde) the iodoform reaction is as follows :



It also gives Felling’s test which is the way to identify it as an aldehyde :



Compound ‘C’ which is a ketone (acetone) the iodoform reaction is as follows:



But it is unable to give Fehling’s test.


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