Answer :

Given,


Q = 12μc =


V = 1200V


dielectric strength, b = 3 x 106V/m


Plate Area can be calculated as follows –


The separation between the plates of the capacitor is given by-



where v is the applied voltage and b is the dielectric strength




Now, the capacitance of the capacitor is given by



where Q is the charge stored and V is the voltage applied.




We know, capacitance c is given by-



Where,


A= Plate Area


d= separation between the plates,


0 = Permittivity of free space = 8.854 × 10-12 m-3 kg-1 s4 A2


Thus, the area of the plates is given by –




A= m2


=0.45 m2


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