Q. 255.0( 1 Vote )
Radius of bubble at the bottom of deep river R1=2.0mm=2.0m
Depth of the river h=3.3m
Density of water = 1000 kg m–3
We know that
Pressure at depth inside a fluid is related to atmospheric pressure by relation
P1=Pa + hg
Where P1 =pressure at depth h
Pa=atmospheric pressure=1.0 × 105 Pa
g=acceleration due to gravity=9.8ms-2
=density of fluid.
Temperature is same for both water at the bottom and the water at the surface. So, we can apply Boyle’s law which says that PV=constant, when temperature is constant.
Let V1 be the volume of air bubble at bottom of deep river
Va be the volume of air bubble at surface of river
Where Ra = radius of bubble at surface of river
So, according to Boyle’s law
P1 V1=Pa Va
Radius of the air bubble at the surface of river is 2.210-3m.
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