# An aeroplane is flying horizontally with a velocity of 600 kmhr–1 and at the height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

Aeroplane moves horizontally

Hence horizontal velocity = u = 600 kmhr–1

Height = h = 1960 m

Now, horizontal velocity remains constant as acceleration acts vertically. For horizontal range AB =

Horizontal Velocity × Time of flight

Let the time of flight = T

Now for, Vertical Motion:

s = h; u = 0; a = g; t = T;

Using equations of motion:   So, Now, u = 600 kmhr–1 = So, Rate this question :

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