Answer :

Here the neutron is in thermal equilibrium with matter and it have a kinetic due which depends upon temperature of surrounding


We have a relation to find kinetic energy of a atomic particle at any Temperature which is



Where EK is the kinetic energy of particle at temperature T and K is Boltzmann constant


K = 1.38 × 10-23 JK-1


Here temperature is


T = 300 K


So linetic energy of neutron is



So kinetic energy of neutron is


Ek = 6.21 × 10-21J


And we know Kinetic energy of a particle is given by the relation



Where vis the speed of the particle and m is the mass of the particle


Multiplying both side sides by m



Or


So we get



We know de-Broglie wavelength of a particle is given by relation



where 𝜆 is the de-Broglie wavelength of a particle having mass m and moving with velocity v, h is Planck’s constant


putting the value of


in above equation we get de Broglie wavelength



Here the particle is neutron and we know mass of neutron


m = 1.66 × 10-27Kg


Value of Planck’s constant


h = 6.63 × 10-34Js


and kinetic energy of neutron is


Ek = 6.21 × 10-21J


Putting values in above equation we get




Or 𝜆 = 0.146 × 10-9m = 0.146 nm


So the de Broglie wavelength of neutron is 0.146 nm


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Calculate the de-Physics - Board Papers

(a) Plot a graph Physics - Board Papers

Plot a graph showPhysics - Board Papers

Answer the followNCERT - Physics Part-II

An electron (massPhysics - Exemplar