Answer :
Here S = {1, 2, 3, 4, 5, 6}
(i) A = {1, 2, 3, 4, 5, 6}
(ii) B = φ
(iii) C = {3, 6}
(iv) D = {1, 2, 3}
(v) E = {6}
(iv) F = {3, 4, 5, 6}
A ∪ B = {1, 2, 3, 4, 5, 6} ∪ ϕ
={1, 2, 3, 4, 5, 6}
A ∩ B = {1, 2, 3, 4, 5, 6} ∩ φ = φ
B ∪ C = φ ∪ {3, 6}={3, 6}
E ∩ F = {6} ∩ {3, 4, 5, 6} = {6}
D ∩ E = {1, 2, 3} ∩ {6} = φ
A- C = {1,2.3,4,5,6} - {3,6} = {1,2,4,5}
D - E = {1,2,3} - {6} = {1,2,3}
F' = S - F = {1, 2, 3, 4, 5, 6} - (3, 4, 5, 6} = {1,2}
E ∩ F' = {6} ∩ {1, 2} = φ.
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