Also, find A ∪ B, A ∩ B, B ∪ C, E ∩ F, D ∩ F, A - C, D - E, F', E ∩ F'.

Here S = {1, 2, 3, 4, 5, 6}

(i) A = {1, 2, 3, 4, 5, 6}

(ii) B = φ

(iii) C = {3, 6}

(iv) D = {1, 2, 3}

(v) E = {6}

(iv) F = {3, 4, 5, 6}

A ∪ B = {1, 2, 3, 4, 5, 6} ∪ ϕ

         ={1, 2, 3, 4, 5, 6}

A ∩ B = {1, 2, 3, 4, 5, 6} ∩ φ = φ

B ∪ C = φ ∪ {3, 6}={3, 6}

E ∩ F = {6} ∩ {3, 4, 5, 6} = {6}

D ∩ E = {1, 2, 3} ∩ {6} = φ

A- C = {1,2.3,4,5,6} - {3,6} = {1,2,4,5}

D - E = {1,2,3} - {6} = {1,2,3}

F' = S - F = {1, 2, 3, 4, 5, 6} - (3, 4, 5, 6} = {1,2}

E ∩ F' = {6} ∩ {1, 2} = φ.