Answer :

Given,

The radius of the weapon, r=0.5 m


Therefore, Surface area, A=4𝜋r2 = 𝜋


Temperature after detonation, T=106 K


Stefan’s constant, σ = 5.67 × 10-8 W/ m2K4


(a) Therefore, power radiated (P) is given by



(ANS)


(b) Here, 10% of the energy(E) is to evaporate water which is at 30°C. This means the energy heats the water up to 100°C and then evaporates.


So, 0.1E = msΔT +mLv


Here, the first term is due to the contribution of energy in heating the liquid to 100°C and the second term is due to vaporization and m is the mass of the water used.


Energy,


Here, t is the time which is 1 sec.


Given, Heat capacity, Sw = 4186.0 J/ kgK


Latent heat of vaporization, Lv = 22.6 X 105 J / kg


Temperature difference, ΔT = 100°C - 30°C = 70°C





So, 7x109 kg of water would be evaporated.


(c) Here, energy,


Therefore, momentum,


Now, momentum at a distance 1km (per unit time) is



Therefore, the momentum imparted at 1km is 47.7 N/m2


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