# a1 = 3 an = 3an – 1 + 2, for all n > 1

a1 = 3

an = 3an – 1 + 2, for all n > 1

For n = 2, a2 = 3an – 1 + 2, for all n > 1

= 3a1 + 2 = 3 × 3 + 2 = 11
For n = 3, a3 = 3a2 + 2 = 3 × 11 + 2 = 35
For n = 4, a4 = 3a3 + 2 = 3 × 35 + 2 = 107
For n = 5, a5 = 3a4 + 2 = 3 × 107 + 2 = 323

Hence the required sequence is

3, 11, 35, 107, 323+……..

Corresponding series

= 3 + 11 + 35 + 107 + 323+……..

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