Answer :

(a) (i) CH3CHO + HCN CH3-CH(CN)-OH


(ii) CH3CHO + H2N-OH CH3CH=N-OH


(iii)


(b) (i) Add neutral FeCl3 in both the solutions, phenol forms violet colour but benzoic acid does not.


(ii) Tollen’s reagent test: Add ammonical silver nitrate (Tollen’s reagent) in both the solutions. Propanal gives silver mirror whereas propanone does not.


OR


(a) (i) Chlorine acts as electron withdrawing group, so it helps in dispersing the negative charge on carboxylate ion after releasing of H+ ions and thus making it stable. So, Cl-CH2COOH is stronger acid than CH3COOH


(b) (i) Rosenmund reduction:


Or



(ii) Cannizzaro’s Reaction:


(c) CH3CH2-CH2-CO-CH3 shows iodoform test because it has a terminal methyl ketone group.


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