Answer :

Concepts/Formula used:


Ohm’s Law:


Potential Difference (V) across a resistor of resistance R when current I passes through it is given by Ohm’s law:



Ammeter:


It consists of a galvanometer coil in parallel with a stunt resistance.


Kirchhoff’s junction rule:


The sum of currents entering a junction is equal to the sum of currents leaving it.


The given voltmeter looks like this:



The maximum potential difference that can be measured is ,and let the current through the voltmeter for maximum deflection be .


Note that the coil (r) and the other resistor (R) are in series.






(Note that 1kΩ = 1000Ω )


Now, using Ohm’s law,





The ammeter we want looks like the following diagram:



The maximum current that can be measured is .


From our previous calculations we know that the current through the coil for maximum deflection is .


Note that the shunt resistance (rs) and the coil (r) are parallel in an ammeter.


By Kirchhoff’s junction rule,





Using Ohm’s law, we have



and



As rs and r are in parallel, the potential difference across them is the same.







Hence, the shunt resistance is 0.251Ω.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USPhysics - Exemplar

<span lang="EN-USPhysics - Exemplar

Let there be n rePhysics - Exemplar

<span lang="EN-USPhysics - Exemplar

<span lang="EN-USPhysics - Exemplar

Two cells of emf Physics - Exemplar

<span lang="EN-USPhysics - Exemplar

<span lang="EN-USPhysics - Exemplar

Kirchhoff ’s juncPhysics - Exemplar