Answer :

Given


Mass of oxygen gas =1.60g


Mass of nitrogen gas =2.80g


Temperature of vessel=300K


Volume of vessel=0.166m3


We know that


Number of moles n=


Molar mass of oxygen= 32g/mol


Molar mass of nitrogen=28g/mol


Number of moles of oxygen n1 =


Number of moles of nitrogen n2=


We know ideal gas equation


PV=nRT


Where V= volume of gas


R=gas constant=8.31Jmol-1K-1


T=temperature


n=number of moles of gas


P=pressure of gas


In a mixture of non-interacting ideal gases, the pressure that a gas in a mixture of gases would exert if it occupied the same volume as the mixture at the same temperature is called the partial pressure of that gas.


Partial pressure of oxygen gas



Partial pressure of nitrogen gas



According to Dalton’s law of partial pressure, the total pressure of a mixture of ideal gas is the sum of partial pressures.


So, total pressure


P=Po+PN =750+1500=2250Pa


The pressure of the mixture of oxygen and nitrogen gas is 2250Pa.


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