Answer :

Given:


number of moles, n = 1


Specific heat at constant temperature, Cv(monoatomic gas) = 3R/2 = 12.471 J/mol/K


R = universal gas constant = 8.314 J/mol/K


Initial velocity(vi) = 50 m/s


Final velocity(vf) = 0


Molecular weight(m) = 20 g/mol = 0.02 kg/mol


Formula Used:


i. Change in internal energy(dU) = nCvdT,


Where,


n is the number of the moles of the gas,


Cv is the heat capacity at the constant volume


dT = rise in temperature.


ii. Mechanical energy lost,


Where,


m is the molecular weight of the gas in kg


vi is the initial velocity,


vf is the final velocity,


equating equation (i) and (ii), we get


Putting the values in the above equation, we get



=> dT = rise in temperature ~ 2 K (Answer).


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