Q. 11

(a) Using valence

Answer :

(a) Fe exists in +2 oxidation state in [Fe(CN)6]4-.

Electronic configuration of Fe+2 = 3d6


As CN is a strong field ligand, there will be pairing of electrons in d orbital.

Hybridization and shape of [Fe(CN)6]4- is d2sp3 and octahedral respectively.

Since, there is no unpaired electron present therefore, the complex is diamagnetic in nature.

(b) (i) When Δo< P, the electronic configuration of d6 will be t2g3eg3.

(ii) When Δo > P, the electronic configuration of d6 will be t2g6eg0.

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