Q. 385.0( 2 Votes )

A uniform chain o

Answer :

Mass of the part of chain on the table = 2m/3

Mass of the part hanging from the table = m - 2m/3 = m/3

Similarly, length of the part of chain on the table = 2l/3

Length of the part of chain hanging from the table = l/3

⇒ Centre of the mass m/3 will be at l/6

Potential energy of the part hanging =

= mgl/18

∴ Work done to put the hanging part back on table = mgl/18

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation