Q. 385.0( 2 Votes )
A uniform chain o
Answer :
Mass of the part of chain on the table = 2m/3
Mass of the part hanging from the table = m - 2m/3 = m/3
Similarly, length of the part of chain on the table = 2l/3
Length of the part of chain hanging from the table = l/3
⇒ Centre of the mass m/3 will be at l/6
Potential energy of the part hanging =
= mgl/18
∴ Work done to put the hanging part back on table = mgl/18
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