Q. 383.7( 3 Votes )

A uniform chain o

Answer :

Mass of the part of chain on the table = 2m/3

Mass of the part hanging from the table = m - 2m/3 = m/3

Similarly, length of the part of chain on the table = 2l/3

Length of the part of chain hanging from the table = l/3

⇒ Centre of the mass m/3 will be at l/6

Potential energy of the part hanging =

= mgl/18

∴ Work done to put the hanging part back on table = mgl/18

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