Q. 154.2( 24 Votes )
A train starts fr
Answer :
a. Here initial velocity, u=0
Let v be the final velocity
Acceleration, a=2 m/s2
Now, at t=30 s
We know,
When breaks are applied u1=60 m/s
v1=0
t=60 s
Total distance moved is
b. Maximum speed attained by the train is v= 60 m/s
c. Half the maximum speed=60/2=30 m/s
When acceleration of the train, a=2 m/s2
When the train is decelerating with, a1=-2 m/s2
Position from the starting point is 900+1350=2250 m=2.25 km
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