Answer :

(a) The frequency can be calculated by,



Here,


f0=500Hz


v0= 108 km/h =30m/s


vs=108 km/h = 30m/s


v=340m/s




(b)


For a person near the track,



f0=500Hz


vs= 108 km/h =30m/s


v=340m/s




(c)


500 Hz by the passenger and 458 by the person near the track


Introduction of the speed of the medium changes both the source and observer speed in the equation. For the passenger onboard



And



Hence



For the person outside,




Hence





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