Q. 9 C3.7( 36 Votes )

# Solve the followi

1 g of ice needs 80 cal to become water at 0 C.
1 g of water needs 50 cal to rise to 50 C from 0 C.
So total the heat needed is 150×80 + 150×50 = 19500 cal.
1 g of steam will supply 540 c to become water at 100 C.
1 g of water at 100 C will supply 50 cal to become water at 50 C.
Hence x gram of steam at 100 C will supply 590 cal while cooling to 50 C.
Hence 19500 = 590 x.
Solving, x = 33.05 gram.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Read the followinMHB - Science and Technology Part-1

Solve the followiMHB - Science and Technology Part-1

Solve the followiMHB - Science and Technology Part-1

Solve the followiMHB - Science and Technology Part-1

Solve the followiMHB - Science and Technology Part-1

What is meant by MHB - Science and Technology Part-1