Q. 24 B5.0( 1 Vote )

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Answer :

a) Given:


Conductivity (K) = 3.905 x 10-5 S cm-1


C = 10-3 mol /L


λ° (H+) = 349.6 S cm2 mol-1


λ° (CH3COO-) = 40.9 S cm2 mol-1


First we will calculate molar conductivity (^m) by applying the formula given below:




^m = 39.05 S cm2 mol-1


CH3COOH CH3COO- + H+


λ° (CH3COOH) = λ° (H+) + λ° (CH3COO-)


349.6 S cm2 mol-1 + 40.9 S cm2 mol-1


390.5 S cm2 mol-1


Now, to calculate the degree of dissociation, we apply the formula:




α = 0.1


Thus, degree of dissociation is 0.1


b) Electrochemical cell: It is a device used to convert chemical energy produced in a redox reaction into electrical energy.


It involves two half reactions. Example


Zn + Cu2+ Zn2+ + Cu


We have,


Zn Zn2+ + 2e- (oxidation half reaction)


Cu2+ + 2e- + Cu (reduction half reaction)


The electrode on which oxidation half reaction occurs is called anode and the other on which reduction occurs is called cathode.



If external potential applied becomes greater than of electrochemical cell, the reaction gets reversed and starts in the opposite reaction and the current flows in the opposite reaction.


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