Q. 164.0( 4 Votes )

# A student focused

Given: object distance u = -40 cm

Image distance v =90 -50 = +40 cm

Applying the lens formula:

Therefore, focal length f= +20 cm

(b)Since object is shifted from 10 cm to 30 cm w.r.t 50 cm

So, the object distance u becomes = -20 cm

Focal length = +21 cm

Applying the lens formula, we get

therefore image distance v=1/0 i.e. infinity

(c) When the object gets shifted from 30 cm towards 50 cm, then the object will lie between focus and optical centre of lens and the image formed will be virtual, erect and enlarged in size and also behind the lens.

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