Q. 164.0( 4 Votes )

A student focused

Answer :

Given: object distance u = -40 cm

Image distance v =90 -50 = +40 cm

Applying the lens formula:

Therefore, focal length f= +20 cm

(b)Since object is shifted from 10 cm to 30 cm w.r.t 50 cm

So, the object distance u becomes = -20 cm

Focal length = +21 cm

Applying the lens formula, we get

therefore image distance v=1/0 i.e. infinity

(c) When the object gets shifted from 30 cm towards 50 cm, then the object will lie between focus and optical centre of lens and the image formed will be virtual, erect and enlarged in size and also behind the lens.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
All GrammarAll GrammarAll Grammar41 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

An object of heigScience - Board Papers

Only one of the fLakhmir Singh & Manjit Kaur - Physics

State whether conLakhmir Singh & Manjit Kaur - Physics

Copy and coLakhmir Singh & Manjit Kaur - Physics

<span lang="EN-USScience - Board Papers