Q. 345.0( 1 Vote )

# A string is wrapped on a wheel of moment of inertia 0.20 kg-m2 and radius 10 cm and goes through a light pulley to support a block of mass 2.0 kg as shown in figure (10-E5). Find the acceleration of the block. The acceleration of the block is given as Given

The moment of the inertia of the wheel is given as 0.20 and a radius of 10 cm to support/hang a block of 2 kg mass.

Formula Used

The formula used to find the torque applied on the pulley due to the masses are described below as the product of moment of Inertia and angular acceleration: where is the torque of the pulley, is the angular acceleration and I is the moment of Inertia of the pulley

Explanation

The tension applied by the block on the string is given as The torque of the pulley is given as Hence, making the moment of Inertia of the pulley as Now calculating the acceleration in terms of angular acceleration is   Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  A Lecture on Head-on Collision49 mins  Inelastic collisions in 1 D44 mins  Pseudo Force52 mins  Understand Newton's 2nd law Exhaustively34 mins  Basics strengthener - Newton Laws of motion61 mins  Getting the basics of Gravitation51 mins  Viscosity | World of Fluids51 mins  Elaborative Lecture on Constraint Motion59 mins  NLM HCV Objective | Interactive Quiz63 mins  Questions Based on Equilibrium of a particle37 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 