Answer :

The angular velocity of the stone in circular motion is given as,

ω =


where,


‘v’ is the linear velocity


‘r’ is the radius of the circle.


‘n’ is the number of revolutions per second


The centripetal force for the stone is provided by the tension T of the string,



The centripetal force ‘Fc’ can be given as


Fc ω2r = m (2πn)2 r


And Fc = Tension in the string


Where, m


Given,


Mass of the stone, m= 0.25 kg


Radius of the circle, r= 1.5 m


Number of the revolution per second, n =


n=


Thus,


T= Fc =


T = 6.57 N


The tension in the string is 6.57 N


Given,


The maximum tension that the string can withstand is, T’ =200 N


T’=


v’=


Where, v’ is the maximum velocity of the stone


v’ =


The maximum speed of the stone is 34.64 m/s


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