Answer :

The angular velocity of the stone in circular motion is given as,

ω =

where,

‘v’ is the linear velocity

‘r’ is the radius of the circle.

‘n’ is the number of revolutions per second

The centripetal force for the stone is provided by the tension T of the string,

The centripetal force ‘F_{c}’ can be given as

F_{c} ω^{2}r = m (2πn)^{2} r

And F_{c} = Tension in the string

Where, m

Given,

Mass of the stone, m= 0.25 kg

Radius of the circle, r= 1.5 m

Number of the revolution per second, n =

⇒ n=

Thus,

T= F_{c} =

⇒ T = 6.57 N

The tension in the string is 6.57 N

Given,

The maximum tension that the string can withstand is, T’ =200 N

T’=

⇒ v’=

Where, v’ is the maximum velocity of the stone

⇒ v’ =

The maximum speed of the stone is 34.64 m/s

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