Q. 184.8( 4 Votes )

(a) State Bohr’s

Answer :

a) Bohr’s postulate, for stable orbits, states


“The electron, in an atom, revolves around the nucleus only in those orbits for which its angular momentum is an integral multiple of h/2π” , where h = Planck’s constant.


De Broglie wavelength of a particle is given as



Where λ = wavelength of the moving particle


h = Planck’s constant = 6.63× 10-34 Js


p = momentum of moving particle


We know that momentum is given as


p = m× v


where m = mass of the particle


v = velocity of the particle



For a stable orbit, we must have circumference of the


orbit = nλ (n = 1,2,3, ... ... . )




Thus de –Broglie showed that formation of stationary pattern for


integral “n‟ gives rise to stability of the atom.


b) We know that for hydrogen atom the energy of nth level is given as



According to question, hydrogen atom is excited from ground state (n = 1) to n = 4 level. So, the energy of photon will be


E4-E1 = hν


Where h = Planck’s constant


ν = frequency of the photon absorbed.


Therefore, we can write





the frequency of absorbed photon is 3.1× 1015 Hz.


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