Q. 315.0( 1 Vote )

A square loop PQRS carrying a current of 6.0 A is placed near long wire carrying 10 A as shown in figure (35-E10). A Show that the magnetic force acting on the part PQ is equal and opposite to that on the part RS. B Find the magnetic force on the square loop.



Answer :

Here, current in the wire is


Current in the loop,


Force on an element dx in the arm PQ a distance x away is




similarly, force on RS is,



Hence,.


B distance of PS from wire,


distance of PS from RQ,


Force on element PS is



towards right


Now distance of RQ from wire,


distance of RQ from PS,


similarly, force on RQ is



towards left


Net force,


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