Q. 58
A square coil of edge ℓ having n turns carries a current i. It is kept on a smooth horizontal plate. A uniform magnetic field B exists in a direction parallel to an edge. The total mass of the coil is M. What should be the minimum value of B for which the coil will start tipping over?
Answer :
Given-
Number of turns in the coil = n
Edge of the square loop = l
Magnetic field intensity = B
Magnitude of current = i
Angle between area vector and magnetic field, θ = 90°
Torque acting on the coil,
Where
B= applied magnetic field
A= area of rectangular loop
I = current flowing through coil
= angle between the area vector and magnetic field
Torque produced due to weight is
given by,
where m is the mass
g is the acceleration due to gravity
For the coil to start tipping towards downwards,
For minimum value of B,
From (1) and(2)
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