Answer :

The charge Q is uniformly distributed over its surface, according to Gauss’ law, ,


Where


E = electric field,


Φ = electric flux flowing out through the surface


ds = surface area element, q = charge enclosed, 𝜖0 = electric permittivity in vacuum.


Here, the charge enclosed inside the shell is 0, since the electric charge on the shell is accumulated on the surface of the shell and so the electric field inside the shell will also be 0 since q in Gauss’ equation is 0.


Even if the shell is hammered to reshape it, the charge is not altered, it still there is no charge inside in the center of the shell. Hence, the electric field will remain zero inside the shell even after the reshaping the shell.


Even if the charge is made of metal, the field inside will remain 0 since the charge remains on the surface.


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