Q. 9

# A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350 m s-1. (a) By how much is the phase changed at a given point in 2.5 ms? (b) What is the phase difference at a given instant between two points separated by a distance of 10.0 cm along the direction of propagation?

Given:
Speed of sound in air

Frequency of sound wave

(a) As we know,

Distance travelled by the particle:

Phase difference is given by:

On substituting the values, we get:

(b) For the second case:
Distance between the two points:

On substituting the respective values in the above equation, we get:

The phase difference between the two points is.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Standing Wave44 mins
Sound Wave43 mins
Energy & Power of a Wave60 mins
Transmitted & Reflected Waves39 mins
String Wave51 mins
SHM | Introductory class52 mins
Energy in SHM42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses