Q. 95.0( 1 Vote )

A solution of <sp

Answer :


T =

C = 5 A

Charge =

Q =

Q = 6000 C

According to the reaction,

Nickel deposited by 2 = 58.7

Thus, Ni deposited by 6000 C =

= 1.82 g

Therefore, 1.82 g of Ni will be deposited at the cathode.

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