(a) The mass of the solid substance
Specific heat capacity of the substance = 500J kg–1 K–1
Energy to change temperature from 0C to 80C = 1000J
Mass = ?
Q = mc(ΔT)
m is the mass (Kg)
c is the specific heat of ice (J/kg-K)
ΔT is the temperature difference(K)
ΔT = 80
C = 500
Q = 1000
M = ?
500 J/kg-K × 80K × m(kg) = 1000J
M = 25gm
(b) the latent heat of fusion of the substance
Mass of ice = 25gm
Energy from B to C = 1000J (to convert ice to water)
Latent heat of fusion = ?
Q = mF
where m is the mass (Kg)
F is the latent heat of fusion of ice (J/kg)
Q = 1000J
M = 25gm = 0.025 kg
F = ?
F J/Kg × 25/1000Kg = 1000J;
latent heat of fusion is 40000J/Kg.
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