Q. 25.0( 1 Vote )

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Answer :

(a) The mass of the solid substance

Given


Specific heat capacity of the substance = 500J kg–1 K–1


Energy to change temperature from 0C to 80C = 1000J


(from Graph)


Mass = ?


Formula used


Q = mc(ΔT)


m is the mass (Kg)


c is the specific heat of ice (J/kg-K)


ΔT is the temperature difference(K)


ΔT = 80


C = 500


Q = 1000


M = ?


500 J/kg-K × 80K × m(kg) = 1000J


M = 25gm


(b) the latent heat of fusion of the substance


Given


Mass of ice = 25gm


Energy from B to C = 1000J (to convert ice to water)


Latent heat of fusion = ?


Formula Used


Q = mF


where m is the mass (Kg)


F is the latent heat of fusion of ice (J/kg)


Q = 1000J


M = 25gm = 0.025 kg


F = ?


F J/Kg × 25/1000Kg = 1000J;


latent heat of fusion is 40000J/Kg.


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