Q. 25.0( 1 Vote )

A solid of initial temperature 0°C is heated. A graph showing changes in the temperature according to the heat supplied is given below.

Based on the graph calculate the following. (Specific heat capacity of the substance: 500J kg–1 K–1)

(a) the mass of solid substance

(b) the latent heat of fusion of the substance

Answer :

(a) The mass of the solid substance


Specific heat capacity of the substance = 500J kg–1 K–1

Energy to change temperature from 0C to 80C = 1000J

(from Graph)

Mass = ?

Formula used

Q = mc(ΔT)

m is the mass (Kg)

c is the specific heat of ice (J/kg-K)

ΔT is the temperature difference(K)

ΔT = 80

C = 500

Q = 1000

M = ?

500 J/kg-K × 80K × m(kg) = 1000J

M = 25gm

(b) the latent heat of fusion of the substance


Mass of ice = 25gm

Energy from B to C = 1000J (to convert ice to water)

Latent heat of fusion = ?

Formula Used

Q = mF

where m is the mass (Kg)

F is the latent heat of fusion of ice (J/kg)

Q = 1000J

M = 25gm = 0.025 kg

F = ?

F J/Kg × 25/1000Kg = 1000J;

latent heat of fusion is 40000J/Kg.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Introduction to Heat48 mins
Fundamentals of Heat Energy47 mins
Heat dissipated in a Circuit39 mins
Quiz| Imp. Qs. on Heat Dissipation30 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses