Q. 225.0( 1 Vote )

# A soft drink bottle is dropped by a water from the top of a hotel whose height is 100 m. It takes T second to reach the ground. Where will it be at T/2 second?

A. 50 m from top

B. 75 m from bottom

C. 25 m from bottom

D. 40 m from top

Answer :

Given:

Height of Tower = 100 m

Time taken to reach ground = T seconds

Acceleration = a = g = 9.8 ms^{-2}

Initial Speed = u = 0

Final Speed = v

Now, we know that,

At t = T and s = 100 m …..1

Let t = and s = x

Then, …..2

So, dividing equation 1 by 2, we get,

x = 25 m

So, 25 m from the top at t = seconds or (100 – 25) m, that is 75 m from the bottom at seconds.

Hence, option B is correct.

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