# A short bar magne

Given:

Angle between axis of bar magnet and external magnetic field, θ = 30°

Strength of external magnetic field, B = 0.25 T

Torque experienced by bar magnet, Τ = 4.5 × 10-2J

We know that, when a Bar magnet is placed in a uniform magnetic field it experiences a Net torque given by,

T = M × B …(1)

T = M × B × Sinθ

Where,

M = magnetic moment

T = Torque on bar magnet

θ = angle between magnetic field and magnetic moment

From equation (1) we can write,

M = 0.36 JT-1

Hence, the magnitude of moment of the Bar magnet is 0.36JT-1.

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