Q. 44.0( 5 Votes )

# A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of radius 30 m. What horizontal force on the scooter is needed to make the turn possible?

Answer :

Velocity of the scooter, v = 36 km/hr

= 36 × 5/18 m/s

= 10 m/s

Mass of the scooter, M = 150 kg

The turn will be possible when the both the forces acting on the scooter, radially inward and outwards the turn balance out.

⇒ Horizontal force required = centripetal force

=Mv^{2}/Radius

=150×10×10/30

=500 N

Rate this question :

An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15°. What is the radius of the loop?

NCERT - Physics Part-IThe displacement vector of a particle of mass m is given by r (t) = î A cos ωt + ĵ B sin ωt.

(a) Show that the trajectory is an ellipse.

(b) Show that F = −mω^{2}r

Physics - Exemplar

A motorcycle is going on an over bridge of radius R. The driver maintains a constant speed. As the motorcycle is ascending on the over bridge, the normal force on it

HC Verma - Concepts of Physics Part 1