Q. 94.3( 36 Votes )

# A sample of drinking water was found to be severely contaminated with chloroform (CHCl_{3}) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass):

(i) express this in percent by mass

(ii) determine the molality of chloroform in the water sample.

Answer :

Given:

Level of contamination = 15 ppm [by mass]

To find: Mass Percentage and Molality

Formula:

Molality

Mass Percentage of Solute

Solution:

Calculation of Mass Percentage:

15 ppm means 15 parts of Chloroform in 10^{6} parts of drinking water

⇒ Mass Percentage

= 1.5 × 10^{-3}

Calculation of Molality:

⇒ Molecular Mass of Chloroform, CHCl_{3} = [12] + [1] + [35.5 × 3]

= 119.5 g

⇒ Number of Moles of Chloroform = [15 / 119.5]

= 0.1255 moles

Molality

= 1.255 × 10^{-4}

Therefore the Mass Percentage is = 1.5 × 10^{-3} and the Molality of the solution is = 1.255 × 10^{-4} m.

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