Q. 94.1( 46 Votes )

A sample of drink

Answer :

Given:

Level of contamination = 15 ppm [by mass]


To find: Mass Percentage and Molality


Formula:


Molality


Mass Percentage of Solute


Solution:


Calculation of Mass Percentage:


15 ppm means 15 parts of Chloroform in 106 parts of drinking water


Mass Percentage



= 1.5 × 10-3


Calculation of Molality:


Molecular Mass of Chloroform, CHCl3 = [12] + [1] + [35.5 × 3]


= 119.5 g


Number of Moles of Chloroform = [15 / 119.5]


= 0.1255 moles


Molality



= 1.255 × 10-4


Therefore the Mass Percentage is = 1.5 × 10-3 and the Molality of the solution is = 1.255 × 10-4 m.


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