# A sample of drinking water was found to be severely contaminated with chloroform (CHCl3) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass):(i) express this in percent by mass(ii) determine the molality of chloroform in the water sample.

Given:

Level of contamination = 15 ppm [by mass]

To find: Mass Percentage and Molality

Formula:

Molality

Mass Percentage of Solute

Solution:

Calculation of Mass Percentage:

15 ppm means 15 parts of Chloroform in 106 parts of drinking water

Mass Percentage

= 1.5 × 10-3

Calculation of Molality:

Molecular Mass of Chloroform, CHCl3 = [12] + [1] + [35.5 × 3]

= 119.5 g

Number of Moles of Chloroform = [15 / 119.5]

= 0.1255 moles

Molality

= 1.255 × 10-4

Therefore the Mass Percentage is = 1.5 × 10-3 and the Molality of the solution is = 1.255 × 10-4 m.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Solutions - 0743 mins
Relative Lowering in Vapour pressure and Elevation in Boiling point56 mins
Colligative properties | Mastering important concepts46 mins
Elevation in BP | A Thorough lecture43 mins
Ideal & Non Ideal Solutions {Concept Class}39 mins
Quiz | Depression in Freezing Point - 0241 mins
Learn Depression in Freezing Point in an Hour35 mins
Non Ideal Solutions52 mins
Rapid Revision | Chapter - Solutions70 mins
Types of solution on the basis of Raoult's Law44 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses