# A sample of drink

Given:

Level of contamination = 15 ppm [by mass]

To find: Mass Percentage and Molality

Formula:

Molality

Mass Percentage of Solute

Solution:

Calculation of Mass Percentage:

15 ppm means 15 parts of Chloroform in 106 parts of drinking water

Mass Percentage

= 1.5 × 10-3

Calculation of Molality:

Molecular Mass of Chloroform, CHCl3 = [12] + [1] + [35.5 × 3]

= 119.5 g

Number of Moles of Chloroform = [15 / 119.5]

= 0.1255 moles

Molality

= 1.255 × 10-4

Therefore the Mass Percentage is = 1.5 × 10-3 and the Molality of the solution is = 1.255 × 10-4 m.

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