Answer :

If the balloon does not have a spherical surface, the charge enclosed by the surface still remains 0 since the charge Q is distributed only over its surface. Hence, by Gauss’ law,


,


where 𝜖0 is the electric permittivity of vacuum,


𝚽= flux through closed surface, E = electric field, ds = surface element, q = charge enclosed.


Here, q(charge enclosed) = 0. Hence, the flux is 0, which give us that the electric field is also 0 everywhere.


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