# A rubber ball of mass 50 g falls from a height of 10 cm and rebounds to a height of 50 cm. Determine the change in linear momentum and average force between the ball and the ground taking time of contact as 0.1 s.

Initial velocity = 0m/s = u

Mass = 50g = 0.05kg

Final velocity = v

Using 3rd equation of motion

v2 = u2 + 2gh

v2 = 02 + 2(9.8)(0.1)

v2 = 1.96

v = 1.4m/s

For 50cm rebound

Using 3rd equation of motion

v2 = u2 – 2gh

02 = u2 – 2(9.8)(0.5)

u = 3.13m/s

Impulse = change in momentum

= mv–(–mu)

= 0.05kg × 1.4m/s + 0.05kg × 3.13m/s

= 0.2265Ns

Force =

=

= 2.265N

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