Q. 36
A proton is projected with a velocity of 3×106 m–1perpendicular to a uniform magnetic field of 0.6 T. Find the acceleration of the proton.
Answer :
Given-
Velocity of the proton, v = 3 × 106 m s−1
Uniform magnetic field, B = 0.6 T
As per the question, the proton is projected perpendicular to a
uniform magnetic field.
We know, Newton’s second law, Force F is given by –
where
m is mass of the object
a=acceleration
For proton
Magnetic force, we know, Lorentz force F is given by -
where,
e = charge on an electron
v = velocity of the electron
B=magnetic field
θ= angle between B and v
Equating (1) and (2),
As θ = 900
Rate this question :






















A rectangular coil of 100 turns has length 5 cm and width 4 cm. It is placed with its plane parallel to a uniform magnetic field and a current of 2A is sent through the coil. Find the magnitude of the magnetic field B, if the torque acting on the coil is 0.2 N m–1.
HC Verma - Concepts of Physics Part 2A circular coil of radius 2.0 cm ahs 500 turns in it and carries a current of 1.0 A. Its axis makes an angle of 30° with the uniform magnetic field of magnitude 0.40 T that exist in the space. Find the torque acting on the coil.
HC Verma - Concepts of Physics Part 2A rectangular loop of sides 20 cm and 10 cm carries a current of 5.0 A. A uniform magnetic field of magnitude 0.20 T exists parallel to the longer side of the loop.
(a) What is the force acting on the loop?
(b) What is the torque acting on the loop?
HC Verma - Concepts of Physics Part 2
A circular loop carrying a current i has wire of total length L. A uniform magnetic field B exists parallel to the plane of the loop.
(a) Find the torque on the loop.
(b) If the same length of the wire is used to form a square loop, what would be the torque? Which is larger?
HC Verma - Concepts of Physics Part 2
Fe+ions are acceleration through a potential difference of 500 V and are injected normally into a homogeneous magnetic field B of strength 20.0 mT. Find the radius of the circular paths followed by the isotopes with mass numbers 57 and 58. Take the mass of an ion = A(1.6 × 10–27) kg where A is the mass number.
HC Verma - Concepts of Physics Part 2A charged particle moves along a circle under the action of possible constant electric and magnetic fields. Which of the following are possible?
HC Verma - Concepts of Physics Part 2A charged particle moves in a gravity-free space without change in velocity. Which of the following is/are possible?
HC Verma - Concepts of Physics Part 2If a charged particle at rest experiences no electromagnetic force,
HC Verma - Concepts of Physics Part 2If a charged particle goes unaccelerated in a region containing electric and magnetic fields.
HC Verma - Concepts of Physics Part 2