Q. 36
A proton is projected with a velocity of 3×106 m–1perpendicular to a uniform magnetic field of 0.6 T. Find the acceleration of the proton.
Answer :
Given-
Velocity of the proton, v = 3 × 106 m s−1
Uniform magnetic field, B = 0.6 T
As per the question, the proton is projected perpendicular to a
uniform magnetic field.
We know, Newton’s second law, Force F is given by –
where
m is mass of the object
a=acceleration
For proton
Magnetic force, we know, Lorentz force F is given by -
where,
e = charge on an electron
v = velocity of the electron
B=magnetic field
θ= angle between B and v
Equating (1) and (2),
As θ = 900
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