Q. 36

A proton is projected with a velocity of 3×106 m–1perpendicular to a uniform magnetic field of 0.6 T. Find the acceleration of the proton.

Answer :

Given-



Velocity of the proton, v = 3 × 106 m s−1



Uniform magnetic field, B = 0.6 T



As per the question, the proton is projected perpendicular to a


uniform magnetic field.



We know, Newton’s second law, Force F is given by –



where


m is mass of the object


a=acceleration


For proton




Magnetic force, we know, Lorentz force F is given by -



where,


e = charge on an electron


v = velocity of the electron


B=magnetic field


θ= angle between B and v


Equating (1) and (2),




As θ = 900





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