Q. 6

<span lang="EN-US

Answer :

De-Broglie wavelength of a particle is given by:



Where v = speed


V = accelerating potential


Given that, De-Broglie wavelength is same for -particle and a proton.


Change on -particle =2


Mass of -particle= 4


Change on proton =


Mass of proton =






i. 8:1 is the ratio of accelerating potential.






ii. 4:1 is the ratio of speed.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USPhysics - Board Papers

(a) Explain briefPhysics - Board Papers

If Bohr’s quantisNCERT - Physics Part-II

Answer the followNCERT - Physics Part-II

Obtain the first NCERT - Physics Part-II

Choose the correcNCERT - Physics Part-II