Answer :

The de Broglie wavelength is given by



Where =Planck’s constant; =mass of the particle; =momentum and =velocity of the particle


Mass of electron kg; mass of proton kg




.


Therefore, the wavelength of electron is greater than the wavelength of proton

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Consider a 20 W bPhysics - Exemplar

A neutron beam ofPhysics - Exemplar

A particle A withPhysics - Exemplar

The de Broglie waPhysics - Exemplar

Two particles A<sPhysics - Exemplar

(i) In the explanPhysics - Exemplar

A proton and an αPhysics - Exemplar

Show that it is nHC Verma - Concepts of Physics Part 2