Q. 54.2( 5 Votes )

A proton, a neutron, an electron and an α-particle have same energy. Then their de Broglie wavelengths compare as
A. λp = λne > λα

B. λα < λp = λne

C. λepn > λα

D. λe = λp = λn = λα

Answer :

K = 1/2mv2

The four particles have the same energy of K is same for them.


v =





We know, me < mp = mn < mα


Hence, e > p = n > α

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