Answer :

Since electric field is a conservative field, the total mechanical energy will always remain conserved.

When charge is at rest, the initial Kinetic Energy (K.E_{i})

When charge starts moving, the final Kinetic Energy (K.E._{f})

Here, m is the mass of the charged particle and v is the velocity of the charged particle.

*U _{i}* denotes initial potential energy while

*U*denotes final potential energy.

_{f}Since total mechanical energy is conserved

We know that the LHS of the above equation is greater than zero. Thus, the RHS is also greater than zero.

Rate this question :

(a) In a quark moPhysics - Exemplar

A uniform field oHC Verma - Concepts of Physics Part 2

The work done to Physics - Exemplar

A uniform electriHC Verma - Concepts of Physics Part 2

Equipotential surPhysics - Exemplar

If a conductor haPhysics - Exemplar

Two charges q<subPhysics - Exemplar

Two charges –q eaPhysics - Exemplar

Two point chargesPhysics - Exemplar

Calculate potentiPhysics - Exemplar