Q. 21

A police jeep is

Velocity of the police jeep, = 90 km/h = 25 m/s
Velocity of the culprit riding the motorbike,
= 72 km/h = 20 m/s

In 10 seconds, the culprit reaches point B from point A.
Distance covered by the culprit:
s =
= 20 × 10 = 200 m

At time t = 10 s, the police jeep is 200 m behind the culprit.

Relative velocity between the police jeep and the culprit:
(25 – 20) = 5 m/s

Time=Distance to be covered Relative velocity=2005= 40 40 seconds, the police jeep moves from point A to a distance s’ to catch the culprit.
Here,
s‘=
= 25 × 40
s‘= 1000 m = 1.0 km
Thus, the jeep will catch up with the bike 1.0 km away from the turning.

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