Q. 11

# A point source em

Given,
Distance of the source from the table-top (r) = 60 cm or 0.6 m
Let
be the intensity of illumination.

Illuminance directly below the source
is given by,

Let be the illuminance at a point 80 cm away from the initial point.
So,

From the figure, we get

OB = 1 m

Substituting the respective values in the above formula, we get

So, the illuminance at a point on the table-top 80 cm away from the first point is 3.24 lux.

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