Answer :

Given,
Luminous flux = 628 lumen

Angle made by the normal with the x axis
Distance of point, r = 1 m
Since the radiant flux is distributed uniformly in all directions, the solid angle will be
.




Illuminance E is given by:



On substituting the respective values, we get,



So, the illuminance on the area is 40 lux.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A point source emHC Verma - Concepts of Physics Part 1

A student is studHC Verma - Concepts of Physics Part 1

The illuminance oHC Verma - Concepts of Physics Part 1

A point source emHC Verma - Concepts of Physics Part 1

Figure (22-E1) shHC Verma - Concepts of Physics Part 1